6400+x^2=50x^2

Solution for 6400+x^2=50x^2 equation:

6400+x^2=50x^2

We move all terms to the left:

6400+x^2-(50x^2)=0

We add all the numbers together, and all the variables

-49x^2+6400=0

a = -49; b = 0; c = +6400;
Δ = b2-4ac
Δ = 02-4·(-49)·6400
Δ = 1254400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1254400}=1120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1120}{2*-49}=\frac{-1120}{-98}
=11+3/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1120}{2*-49}=\frac{1120}{-98}
=-11+3/7
$